/*  A Program to sum the elements of an array  */

#include<stdio.h>
#include<conio.h>
#define SIZE 10

long sump(int *ar, int n);       // function prototype
main(void)
{
   int marbles[SIZE] = {21, 10, 5, 39, 4, 16, 19, 26, 31, 20};
   long int answer;

   answer = sump(marbles, SIZE);  /* C does not allow arrays to be
				  passed as function arguments.  However
				  we pass the name of the array, which is
				  actually the address of where the
				  array begins. That is, marbles[0].   */

   printf("The total number of marbles is %ld.\n", answer);
   return(0);
}

long int sump(int *ar, int n)    /* Use pointer arithemetic. Recall that
				    ar[] is equivalent to *ar   */
{
   int      i = 0;
   long int total = 0;

   while(i < n)
   {
      total += *ar;              // add array element value to total
      ar++;                      // advance pointer to next array element
      i++;                       // increment loop counter
   }
   return(total);
}